By Gregory Ruetsch, Massimiliano Fatica
CUDA Fortran for Scientists and Engineers indicates how high-performance software builders can leverage the facility of GPUs utilizing Fortran, the ordinary language of clinical computing and supercomputer functionality benchmarking. The authors presume no past parallel computing adventure, and canopy the fundamentals besides top practices for effective GPU computing utilizing CUDA Fortran.
To assist you upload CUDA Fortran to present Fortran codes, the booklet explains find out how to comprehend the objective GPU structure, establish computationally in depth elements of the code, and alter the code to control the information and parallelism and optimize functionality. All of this is often performed in Fortran, with no need to rewrite in one other language. each one inspiration is illustrated with real examples so that you can instantly overview the functionality of your code in comparison.
Leverage the ability of GPU computing with PGI's CUDA Fortran compiler
achieve insights from contributors of the CUDA Fortran language improvement team
contains multi-GPU programming in CUDA Fortran, protecting either peer-to-peer and message passing interface (MPI) approaches
contains complete resource code for the entire examples and several other case studies
obtain resource code and slides from the book's significant other site
Read or Download CUDA Fortran for Scientists and Engineers: Best Practices for Efficient CUDA Fortran Programming PDF
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Extra resources for CUDA Fortran for Scientists and Engineers: Best Practices for Efficient CUDA Fortran Programming
Part_of_snake(,RestSnake,RestSnake,). part_of_snake([_|R],[Ring|Rings],RestSnake,[Ring|RestRings]) :part_of_snake(R,Rings,RestSnake,RestRings). coil_it(,_). coil_it([Line|Lines],odd) :write_elements(Line), nl, coil_it(Lines,even). coil_it([Line|Lines],even) :reverse(Line,Line1), write_elements(Line1), nl, coil_it(Lines,odd). Index 45 2. Index The readability index of a Prolog program clause is defined in terms of the following entities: nlit: the total number of literals in the clause narg: the total number of arguments of literals in the clause ndisj : the total number of disjunctions niff : the total number of if-then-elses neq: the number of occurrences of the literal =/2 neckcut: (0 or 1) whether the clause has a !
We start by constructing the list of pairs [(2,2),(3,3),(5,5)], which is sorted and which has no two pairs with the same first component. In a pair (P,F), P is the smallest power of F that is not in the solution list yet. So, the first component of the first element of the pair-list is the next element in the output we are constructing. e. P∗F) and insert the pair (P∗F,F) into the pair-list, respecting the invariants. You should think about why remove power/3 can actually remove pairs without taking the F-component of the pairs into account.
Divide(Remainder,Divisor,RemQuotList,Repetition) :Remainder10 is 10 * Remainder, Quot is Remainder10 // Divisor, NewRemainder is Remainder10 - Divisor*Quot, divide(NewRemainder,Divisor, [Remainder*Quot|RemQuotList],Repetition). find_repetition([X*Quot|RemQuotList],Remainder,In,Out) :( Remainder == X -> Out = [Quot|In] ; find_repetition(RemQuotList,Remainder,[Quot|In],Out) ). Powers 3. 23 Powers Write a predicate powers/3, which is called with as first argument a list of strictly positive integers, as second argument a strictly positive integer N , and a free third argument.